
Tonight's
Nip/Tuck marks the return of one of the celebrated heroines of primetime serial drama from the 1980s. Joan Van Ark, who made a living out of portraying the ever-enduring, long-suffering meek and mild Valene Ewing on
Knots Landing, guest stars in tonight's episode entitled “Lulu Grandiron.”
Van Ark reunites with fellow
Knots Landing alumna, Donna Mills. They play two women who share more than just Dr. Christian Troy's (
Julian McMahon) surgical expertise.
In tonight's
Nip/Tuck offering, the two former
Knots Landing mainstays play two mature ladies who go under Troy's knife for different cosmetic procedures. Beyond sharing the same plastic surgeon in the operating room however, the women both also savor him in a far more delectable fashion.
"We each had a surgery with Julian McMahon," Van Ark revealed. "We were all in bed with him [in a dream sequence]. It's so un-Valene [referring to her goody-two-shoes
Knots Landing persona], barely any clothes on, bouncing around with Dr. Christian.”
Another blast from the past who is experiencing a re-emergence on primetime via
Nip/Tuck is 1980s heartthrob,
John Schneider. Schneider catapulted to near overnight stardom when he landed the part of Bo on CBS' late `70s to mid-`90s
Dukes of Hazzard. More recently, Schneider essayed the role of Jonathan Kent, Clark's adoptive father on
Smallville.
Schneider has been in several episodes in
Nip/Tuck's current fifth season, as a former adult film star turned movie mogul. His character, Ram Peters, is slated to appear in a multi-episode story arc involving series regular, Kelly Calson's character, Kimber's checkered past.
"Great name, isn't it? He's a bit of a gangster in a nice suit. I like that,” Schneider said of his
Nip/Tuck persona. “Ram may be just enough to eclipse Bo Duke. Kimber used to do porn, and I'm playing a guy she used to work with. But now I own the company that makes the porn, and when people need money, they come to me."
-Rosario Santiago, BuddyTV Staff Columnist
Source: Daily News, USA Today
(Image Courtesy of FX)